Fundamental Concepts
I. Points on triangles:
1. Sum
of the angles of a triangle is 180 degrees.
2 .Sum of
any two sides of a triangle is greater than the third side.
3. Pythagoras theorem: In a
right angle triangle
(Hypotenuse)^2 = (base)^2 + (Height)^2
(Hypotenuse)^2 = (base)^2 + (Height)^2
4.The
line joining the midpoint of a side of a triangle to the opposite vertex is
called the
5.The
point where the three medians of a triangle meet is called CENTROID.
Centroid
divides each of the medians in the ratio 2:1.
6.In an
isosceles triangle, the altitude from the vertex bi-sects the base
7.The
median of a triangle divides it into two triangles of the same area.
8.Area of
a triangle formed by joining the midpoints of the sides of a given triangle is
one-fourth of the area of the given triangle.
II.Points on Quadrilaterals:
1. The diagonals of a parallelogram bisects
each other .
2. Each diagonal of a parallelogram divides
it into two triangles of the same area
3. The diagonals of a rectangle are equal
and bisect each other.
4. The diagonals of a square are equal and
bisect each other at right angles.
5. The diagonals of a rhombus are
unequal and bisect each other at right angles.
6. A parallelogram and a rectangle on the
same base and between the same parallels are equal in area.
7. Of all the parallelograms of a given
sides , the parallelogram which is a rectangle has the greatest
area.
IMPORTANT FORMULAE
I.1.Area
of a rectangle=(length*breadth)
Therefore
length = (area/breadth) and breadth=(area/length)
2.Perimeter
of a rectangle = 2*(length+breadth)
II.Area of
a square = (side)^2 =1/2(diagonal)^2
III Area of four walls of a room = 2*(length + breadth)*(height)
IV 1.Area
of the triangle=1/2(base*height)
2.Area of a triangle = (s*(s-a)(s-b)(s-c))^(1/2),
where a,b,c are the sides of a
triangle and
s= ½(a+b+c)
3.Area
of the equilateral triangle =((3^1/2)/4)*(side)^2
4.Radius
of incircle of an equilateral triangle of side a=a/2(3^1/2)
5.Radius
of circumcircle of an equilateral triangle of side a=a/(3^1/2)
6.Radius
of incircle of a triangle of area del and semiperimeter S=del/S
V.1.Area of
the parellogram =(base *height)
2.Area
of the rhombus=1/2(product of the diagonals)
3.Area
of the trapezium=1/2(size of parallel sides)*distance between them
VI 1.Area of a circle =pi*r^2,where r is the radius
2.
Circumference of a circle = 2∏R.
3.
Length of an arc = 2∏Rθ/(360) where θ is the central angle
4.
Area of a sector = (1/2) (arc x R) = pi*R^2*θ/360.
VII. 1. Area
of a semi-circle = (pi)*R^2.
2.
Circumference of a semi-circle = (pi)*R.
VOLUME AND SURFACE AREA
I. CUBOID
Let
length = 1, breadth = b and height = h units. Then,
1. Volume = (1 x b x h)
cubic units.
2. Surface area= 2(lb + bh + lh) sq.units.
3.
Diagonal.=Öl2 +b2 +h2 units
II. CUBE
Let each
edge of a cube be of length a. Then,
1. Volume = a3 cubic
units.
2. Surface area = 6a2 sq.
units.
3. Diagonal = √3 a units.
Let
radius of base = r and Height (or length) = h. Then,
1. Volume = (Pi r2h)
cubic units.
2. Curved surface area = (2Pi rh).
units.
3. Total surface area =2Pi.r (h+r) sq. units
IV. CONE
Let
radius of base = r and Height = h. Then,
1.
Slant height, l =√ h2+r2
2. Volume = (1/3) Pi.r2h cubic units.
3. Curved surface area = (Pi.rl) sq. units.
4. Total surface area = (Pi.rl + Pi.r2 )
sq. units.
V. SPHERE
Let the
radius of the sphere be r. Then,
1. Volume = (4/3)Pi.r3 cubic units.
2.
Surface area =
(4Pi.r2) sq. units.
VI. HEMISPHERE
Let the
radius of a hemisphere be r. Then,
1. Volume = (2/3)Pi.r3 cubic units.
2. Curved
surface area =
(2Pi.r2) sq. units.
3. Total
surface area =
(3Pi.r2) units.
Remember: 1
litre = 1000 cm3.
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